Files
manual_slop/check_file.py
T
ed f6feab9243 fix(gui): Correct indentation bug in _render_mma_dashboard that caused crash
The code after the 'prior session' return block was incorrectly indented
at 1 space, placing it inside the 'if is_viewing_prior_session' block
instead of after it. This caused 'total_cost' and 'perc' to be undefined
when viewing an active session, triggering an IM_ASSERT error.

Fix: Moved 'track_name', 'track_stats', and 'total_cost' to the
correct 2-space indentation (method body level).
2026-05-06 19:41:22 -04:00

55 lines
1.8 KiB
Python

import sys
def check_ai_client(path):
with open(path, 'r', encoding='utf-8') as f:
lines = f.readlines()
imports = []
internal_imports = []
for i, line in enumerate(lines):
stripped = line.strip()
if stripped.startswith('import ') or stripped.startswith('from '):
if line.startswith('import ') or line.startswith('from '):
imports.append((i+1, stripped))
else:
internal_imports.append((i+1, stripped, line.split(stripped[0])[0]))
print("--- Top-level imports ---")
for lno, imp in imports:
print(f"{lno}: {imp}")
print("\n--- Internal imports ---")
for lno, imp, indent in internal_imports:
print(f"{lno}: [{len(indent)} spaces] {imp}")
print("\n--- Duplicate top-level imports ---")
seen = set()
for lno, imp in imports:
if imp in seen:
print(f"Duplicate: {lno}: {imp}")
seen.add(imp)
print("\n--- Indentation check (first non-space character not at index 0 or multiple of 1) ---")
# Actually, if it's 1-space indentation, any number of spaces is valid at the start?
# No, if it's 1-space indentation, it means each level is 1 space.
# So 0, 1, 2, 3... are all valid.
# BUT if someone used 4 spaces for 1 level, that's wrong.
# The only way to know is to see the context.
# But the prompt says "Ensure the entire file uses exactly 1-space indentation."
# This usually means convert 4-space to 1-space.
# Let's just check for lines starting with 4 spaces that might be 1 level.
# Or better, look for any line where indentation is not exactly 1 space more than parent.
# That's hard without parsing.
# Let's look for common 4-space patterns.
four_spaces = 0
for i, line in enumerate(lines):
if line.startswith(' ') and not line.startswith(' '):
four_spaces += 1
print(f"Lines starting with exactly 4 spaces: {four_spaces}")
if __name__ == "__main__":
check_ai_client('src/ai_client.py')